SOLUTION: A coin is tossed 5 times. Find the probability of getting 4 heads and 1 tail.

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Question 1158074: A coin is tossed 5 times. Find the probability of getting 4 heads and 1 tail.
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
This is 5*(1/2)^4*(1/2)=5/32
for 5 tosses
1--5--10--10--5--1 from Pascal's triangle
0--1--2---3---4--5 heads/tails

Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.

    P = C%5B5%5D%5E4%2A%281%2F2%29%5E5 = 5%2A%281%2F2%29%5E5 = 5%2F32.


Your winning configuration is  (4 heads and 1 tail) of 5 tosses,

and you can get it in 5 different sub-cases.

It is a binomial distribution probability problem with  n= 5;  k= 4  and   p = 1%2F2.