SOLUTION: How many randomly selected employers (minimum number) must we contact in order to guarantee a margin of error of no more than 4% (at 95% confidence)? A.600 B.400 C.550 D.1000

Algebra ->  Probability-and-statistics -> SOLUTION: How many randomly selected employers (minimum number) must we contact in order to guarantee a margin of error of no more than 4% (at 95% confidence)? A.600 B.400 C.550 D.1000      Log On


   



Question 1155541: How many randomly selected employers (minimum number) must we contact in order to guarantee a margin of error of no more than 4% (at 95% confidence)?
A.600
B.400
C.550
D.1000

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
margins of error estimate is 1/sqrt(n)
if 0.04=1/25 is margin of error
then n=25^2 or 625.
Choose 600.