SOLUTION: A box contains 7 yellow, 15 green and 17 red jelly beans. If 2 jelly beans are selected without replacement, what is the probability that: a) Exactly 1 is yellow and 1 is gree

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Question 1155501: A box contains 7 yellow, 15 green and 17 red jelly beans.
If 2 jelly beans are selected without replacement, what is the probability that:
a) Exactly 1 is yellow and 1 is green?
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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There are  7 + 15 + 17 = 39 jelly beans, in all.


    P(1st is yellow, 2-nd is green) = %287%2F39%29%2A%2815%2F38%29 = %287%2A15%29%2F%2839%2A38%29


    P(1st is green, 2-nd is yellow) = %2815%2F39%29%2A%287%2F38%29 = %287%2A15%29%2F%2839%2A38%29


    P(final) = the sum = %282%2A7%2A15%29%2F%2839%2A38%29 = 0.1417.    ANSWER

Solved.