SOLUTION: Assume that a set of test scores is normally distributed with a mean of 120
and a standard deviation of 20
.
Use the 68-95-99.7 rule to find the following quantities.
Algebra ->
Probability-and-statistics
-> SOLUTION: Assume that a set of test scores is normally distributed with a mean of 120
and a standard deviation of 20
.
Use the 68-95-99.7 rule to find the following quantities.
Log On
You can put this solution on YOUR website! The first is the percentage less than the mean. This is half or 50%
The second is (140-120)/20=1 z=(x-mean)/sd
68% are greater than 1 from the mean OR -1 from the mean. Therefore it is 16% that are greater than 1; the other 16% are less than -1 sd s from the mean.
Between 80 and 140, using the same formula, would be between -2 and +1.
Draw the normal curve. Label 3 sd s on either side. From -2 to 0 is 47.5%. From 0 to 1 is 34%. That sum is 81.5%.