SOLUTION: A box contains 5 green marbles, 7 blue marbles, and 9 red marbles.
Three marbles are selected at random from the box, one at a time, without replacement.
Find the probability
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-> SOLUTION: A box contains 5 green marbles, 7 blue marbles, and 9 red marbles.
Three marbles are selected at random from the box, one at a time, without replacement.
Find the probability
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Question 1153539: A box contains 5 green marbles, 7 blue marbles, and 9 red marbles.
Three marbles are selected at random from the box, one at a time, without replacement.
Find the probability that the first two marbles selected are not red, and the last marble is red. Answer by ikleyn(52776) (Show Source):
In all, there are 5+7+9 = 21 marbles.
Of them, 5 are red and 21-5 = 16 are not red.
Therefore, the probability under the question is
P = = 0.150376. ANSWER
