SOLUTION: A club is choosing 2 members to serve on a committee. The club has nominated 1 women and 3 men. Based on chance alone, what is the probability that one woman and one man will be ch

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Question 1151898: A club is choosing 2 members to serve on a committee. The club has nominated 1 women and 3 men. Based on chance alone, what is the probability that one woman and one man will be chosen to be on the committee?
Answer by ikleyn(52795) About Me  (Show Source):
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From nominated 1 women and 3 men, the pair of persons to serve on a committee can be chosen by  C%5B4%5D%5E2 = %284%2A3%29%2F%281%2A2%29 = 2*3 = 6 different ways.


    Here 4 = 1 + 3 is the total number of nominated persons.


We consider here non-ordered pairs, since the difference in their positions/duties is not specified.


Of this total number of pairs, the pairs containing one woman can be selected by 3 different ways.


So, the probability under the question is  3%2F6 = 1%2F2.    ANSWER