SOLUTION: The amount of money that students spend on their cell phones per week is normally distributed with a mean of $52-00 and a standard deviation of $6-00. What is the probability that
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Question 1143865: The amount of money that students spend on their cell phones per week is normally distributed with a mean of $52-00 and a standard deviation of $6-00. What is the probability that a student studies for more than $60-00 per week. Find the probability that the mean amount of money on cell phones for three randomly selected students is less than $60-66 per week Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
z>(60-52)/6 or z>1.33
probability is 0.9176
if this is 60.66
then z<(x bar-60)/6/sqrt(3)
This is z<(0.66)*sqrt(3)/6 or z<0.19 with probability 0.5753
