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Having nothing else given, an appropriate hypothesis is to assume that we have random variable
X = "the number of failures per week"
with integer random values which is uniformly distributed with the minimum value of 0 and the maximum value of 4.
Then the mean average is exactly 2 (=
), as the problem states,
and the condition becomes "consistent with the given part" and "self-closed".
Then the answer to the problem's question is P(X <= 1) =
(X may have values of 0 or 1 of 5 possible integer values from 0 to 4).
Solved.
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See the lesson
- Unusual probability problems
in this site, where you will find many other similar problems solved and explained.