SOLUTION: A bag contains 3 red, 5 white and 4 green balls . Three balls are selected at random without replacement. Find the probability that the three balls chosen are one of each colour
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Question 1142173: A bag contains 3 red, 5 white and 4 green balls . Three balls are selected at random without replacement. Find the probability that the three balls chosen are one of each colour Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 12 balls total
first is 3/12 * second which is 5/11* third, which is 4/10. But there are 6 ways to do this, RWG/RGW/WRG/WGR/GRW/GWR.
or 3C1*5C1*4C1*6/12C3
That joint product is 60/1320, 6 ways or 60/220 or 3/11 or 0.273
