Question 1141475: Suppose you work for an airline and you are taking reservations for a flight on an aircraft that has 152 seats. You know, based on historical flights trends, that if you sell a single ticket there is a 91% chance that the person with the ticket will actually show up for the flight. You decide to try to make a little extra money by overbooking your flight and you sell 160 tickets hoping that not more than 152 people will actually show up for the flight
Explain how this scenario meets the four requirements in the definition of a Binomial Distribution (page 200)
Identify what n and p are in this example
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! fixed n
presumably independent probability of 0.91 here
random sample
two outcomes, show up or not.
n=160
p=0.91
The mean is np
the variance is np((1-p)
the sd is sort (variance)
there is no k.
160, 0.91, 152 is what is inputted
or
Normal approximation
mean is 145.6, sd is 3.62
z<(152-146)/3.62
z<1.66
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