SOLUTION: Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 97 th percentile.
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-> SOLUTION: Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 97 th percentile.
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Question 1137696: Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 97 th percentile. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 97%th percentile is z of +1.88
z=(x-mean)/sd
1.88=(x-50)/7
x=63.16 or 63.2 is 97th percentile.
