Possibilities are these: H,TH,TTH,TTTH,TTTT
So you will either flip 1 time for T, 2 times for TH, 3 times for TTH,
or 4 times for either TTTH or TTTT.
So the possible number of flips are X = 1,2,3, or 4 times.
Answer: the number of possible different values for X is 4.
Edwin