SOLUTION: An investigator wants to estimate chocolate consumption (dichotomous-eat chocolate or do not) in kindergarten students (just one group). How many students would be required to ensu
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Question 1131312: An investigator wants to estimate chocolate consumption (dichotomous-eat chocolate or do not) in kindergarten students (just one group). How many students would be required to ensure a 95% confidence interval estimate to be within 5% of the true proportion (E=0.05)? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! SE is z*sqrt(p*(1-p)/n), use 0.5 for p, as most conservative. z is 1.96
error=0.05
so 0.05=1.96 sqrt (.25/n)
square both sides
0.0025=3.84*.25/n
n=0.96/0.0025
=384
