Question 1128501: Two dice are tossed once,what is the probability of obtaining a sum that is (a) a four (b) a seven (c) an eight.
Answer by math_helper(2461)   (Show Source):
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There are 6x6 = 36 possible ordered outcomes (1,1), (1,2), (1,3), …, (5,6), (6,6).
The possible sums are:
2 (1 way: 1 + 1 )
3 (2 ways: 1+2, 2+1)
4 (3 ways: 1+3, 2+2, 3+1)
5 (4 ways)
6 (5 ways)
7 (6 ways)
8 (5 ways)
9 (4 ways)
10 (3 ways)
11 (2 ways)
12 (1 way)
a) Pr(sum is 4) = 3/36 = 
Parts b and c are found similarly. Message if you need help.
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