SOLUTION: Let S = {a, b, c, d, e, f} with P(b) = 0.26, P(c) = 0.14, P(d) = 0.17, P(e) = 0.15, and P(f) = 0.14. Let E = {a, c, f} and F = {b, d, e, f}. Find P(a), P(E), and P(F). P(a) =

Algebra ->  Probability-and-statistics -> SOLUTION: Let S = {a, b, c, d, e, f} with P(b) = 0.26, P(c) = 0.14, P(d) = 0.17, P(e) = 0.15, and P(f) = 0.14. Let E = {a, c, f} and F = {b, d, e, f}. Find P(a), P(E), and P(F). P(a) =      Log On


   

Question 1125681: Let S = {a, b, c, d, e, f} with P(b) = 0.26, P(c) = 0.14, P(d) = 0.17, P(e) = 0.15, and P(f) = 0.14. Let E = {a, c, f} and F = {b, d, e, f}. Find P(a), P(E), and P(F).

P(a) =

P(E) =

P(F) =
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


This can only be solved if you assume , eliminating the possibility of events with probabilities greater than zero.

Given such an assumption:







You can do your own arithmetic.


John

My calculator said it, I believe it, that settles it