SOLUTION: A journal polled its readers to determine the proportion of wives who, if given a second chance, would marry their husband again.
According to the responses from the survey, 72% o
Algebra ->
Probability-and-statistics
-> SOLUTION: A journal polled its readers to determine the proportion of wives who, if given a second chance, would marry their husband again.
According to the responses from the survey, 72% o
Log On
Question 1121572: A journal polled its readers to determine the proportion of wives who, if given a second chance, would marry their husband again.
According to the responses from the survey, 72% of wives would marry their husbands again.
Suppose a random and independent sample of 5 wives was collected. Define the random variable X as the number of these wives who would marry their husbands again. Use the binomial distribution to find the probability that at most 4 of the wives sampled said they would marry their husbands again.
Select one:
a. 0.998279
b. 0.806508
c. 0.376234
d. 0.193492
Thanks in advance Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! "At most, 4" is the same result as 1-P(5), i.e. 1 minus the chance that all 5 said yes. Which makes the math simpler.
1-(.72)^5=1-.19349= .806508 (b)
