Question 1121477: Construct the indicated confidence interval for the population mean mu using a t-distribution.
cequals0.95, x overbarequals115, sequals10, nequals12
The confidence interval is left parenthesis nothing comma nothing right parenthesis .
(Round to the nearest tenth as needed.)
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! the interval is +/-t0.975, df=11*s/sqrt (n)
2.201*10/sqrt(12=6.35
interval is (108.7, 121.4)
Please help: Both of your answers are incorrect. First, identify the degrees of freedom n minus one.
11 DF
LEVEL OF CONFIDENCE IS 95%,
T-VALUE 0.975, DF=11 IS 2.201. AS THE QUESTION IS STATED, THERE IS NO CRITICAL VALUE, BECAUSE THIS IS NOT HYPOTHESIS TESTING
THE MARGIN OF ERROR IS AS GIVEN.
This is for a mean (x bar) =115, s=10 and n=12.
|
|
|
