Question 1119682: Between 1858 and 2011, carbon dioxide (CO2) concentration in the atmosphere rose from roughly 259 parts per million to 379 parts per million. Assume that this growth can be modeled with an exponential function Upper Q equals Upper Q 0 times left parenthesis 1 plus r right parenthesis Superscript t.
By experimenting with various values of the growth rate r, find an exponential function that fits the data for 1858 and 2011.
r almost equals______________________
(Round to five decimal places as needed.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Between 1858 and 2011, carbon dioxide (CO2) concentration in the atmosphere rose from roughly 259 parts per million to 379 parts per million. Assume that this growth can be modeled with an exponential function Upper Q equals Upper Q 0 times left parenthesis 1 plus r right parenthesis Superscript t.
By experimenting with various values of the growth rate r, find an exponential function that fits the data for 1858 and 2011.
r almost equals______________________
(Round to five decimal places as needed.)
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t = 2011-1850 =
Qo = 259
Q = 379
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Q = Qo(1+r)^t
379 = 259(1+r)^161
(1+r)^161 = 1.4633
161 = log(1.4633)/log(1+r)
log(1+r) = log(1.4633)/161 = 0.0010
1+r = 10^0.0010.. = 1.002367..
r = 0.002367..
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Cheers,
Stan H.
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