SOLUTION: The weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interva

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Question 1117126: The weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 68% of all oranges from this orchard.
Answer by stanbon(75887) (Show Source):
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The weight of oranges growing in an orchard is normally distributed with a mean weight of 5 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 68% of all oranges from this orchard.
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Note:: If 68% is in the middle there must be two tails of 16% each.
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Find the z-value limiting those two tails::
invNorm(0.16) = -1 and -invNorm(0.16) = +1
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Lower weight limit = 5-1*1.5 = 3.5 oz
Upper weight limit = 5+1*1.5 = 6.5 oz
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Cheers
Stan H.
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