SOLUTION: A box contains 44 ​red, 33 white and 44 green balls. Two balls are drawn out of the box in succession without replacement. What is the probability that both balls are the sam

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Question 1116024: A box contains 44 ​red, 33 white and 44 green balls. Two balls are drawn out of the box in succession without replacement. What is the probability that both balls are the same​ color?
Found 2 solutions by Shin123, ikleyn:
Answer by Shin123(626) About Me  (Show Source):
You can put this solution on YOUR website!
There are different combinations,
(r,r) (w,w) (g,g) (r,w) (r,g) (w,g) 3 of the combinations have the same color.+3%2F6=1%2F2=50%25%

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
1.  44 + 33 + 44 = 121.



2.  The probability to get two red balls     = %2844%2A43%29%2F%28121%2A120%29.

    
    The probability to get two white balls   = %2833%2A32%29%2F%28121%2A120%29.


    The probability to get two green balls   = %2844%2A43%29%2F%28121%2A120%29.



3.  The probability to get two balls of the same color is  


      = %2844%2A43%2B33%2A32%2B44%2A43%29%2F%28121%2A120%29 = %284%2A43%2B3%2A32%2B4%2A43%29%2F%2811%2A120%29 = 440%2F%2811%2A120%29 = 40%2F120 = 1%2F3 = 0.3333 = 33.33%.