SOLUTION: A baseball player has a batting average of 0.346, so the probability of a hit is 0,346. Assume that his hitting attempts are independent of each other. Assume that the batter gets
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Question 1114943: A baseball player has a batting average of 0.346, so the probability of a hit is 0,346. Assume that his hitting attempts are independent of each other. Assume that the batter gets up to bat 4 times in each game. Estimate the probability that in 50 consecutive games, there are at least 45 games in which the batter gets at least one hit. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! probability of no hits per game is 0.654^4=0.1829
probability of at least one hit is 0.8171
in 50 games, probability of 45 having at least 1 is 50C45(0.8171)^45*(0.1829)^5=0.0489 ANSWER
