SOLUTION: In a survey of 5100 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want 95% confidence in our estimate of the percentage of

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Question 1113821: In a survey of 5100 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want 95% confidence in our estimate of the percentage of T.V. viewers who watch network news programs.

A) 2.00%

B) 1.34%

C) 1.54%

D) 1.76%

E) 1.12%

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In a survey of 5100 T.V. viewers, 40% said they watch network news programs. Find the margin of error for this survey if we want 95% confidence in our estimate of the percentage of T.V. viewers who watch network news programs.
ME = z*sqrt(p*q/n)
ME = 1.96*sqrt(0.4*0.6/5100) = 1.34%
A) 2.00%
B) 1.34%
C) 1.54%
D) 1.76%
E) 1.12
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Cheers,
Stan H.
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