SOLUTION: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face v

Algebra ->  Probability-and-statistics -> SOLUTION: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face v      Log On


   



Question 1112405: An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
EventA : The sum is greater than .
EventB : The sum is an even number.
Write your answers as exact fractions.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. This sum is recorded as the outcome of a single trial of a random experiment.
Compute the probability of each of the following events:
EventA : The sum is greater than 6.
There are 36 sums.
sums less than or = to 6 are 1/1;1/2;1/3/1/4::2/1;2/2;2/3::3/1;3/2::4/1;4/2
P(sum <=6) = 11/36
P(sum >=6) = 25/36
-------------------------------
EventB : The sum is an even number.::: Ans:: 18/36 = 1/2
------------------------------
Write your answers as exact fractions.
Cheers,
Stan H.
------------