SOLUTION: Hi can you please help me with this question (its to do with arrangments/combinations):
A student representative committee of 5 is to be chosen from 4 males and 6 females. How m
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-> SOLUTION: Hi can you please help me with this question (its to do with arrangments/combinations):
A student representative committee of 5 is to be chosen from 4 males and 6 females. How m
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Question 1111646: Hi can you please help me with this question (its to do with arrangments/combinations):
A student representative committee of 5 is to be chosen from 4 males and 6 females. How many committees could be selected which contain more females than males?
Thankyou. Answer by ikleyn(52778) (Show Source):
There are 3 possible configurations:
1. 3 females and 2 males;
2. 4 females and 1 male;
3. 5 females (and 0 males).
In case 1 the number of combinations is ..
In case 2 the number of combinations is ..
In case 3 the number of combinations is ..
Now your task is calculate each of the 3 numbers and then calculate their sum.
If you still have questions, do not hesitate to message to me.
You can do it through the "Thank you" form/window.
In this case, refer to the problem ID number, which is 1111646.
