Question 1111441: The admissions office of a private university released the following data for the preceding academic year: From a pool of 4200 male applicants, 40% were accepted by the university, and 40% of these subsequently enrolled. Additionally, from a pool of 3300 female applicants, 45% were accepted by the university, and 40% of these subsequently enrolled. What is the probability of each of the following?
(a)
A male applicant will be accepted by and subsequently will enroll in the university?
(b)
A student who applies for admissions will be accepted by the university?
(c)
A student who applies for admission will be accepted by the university and subsequently will enroll?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! A male accepted and enrolled is 0.4*0.4=0.16 probability.
7500 apply
672 men enter, 4200*0.16
594 women enter, 3300*0.18
1680 men are accepted and 1486 women are accepted or a total of 3146
random probability a student will be accepted is 3146/7500 or 0.419.
672+594=1266 accepted and enter for a probability of 0.1688
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