An elevator with two passengers stops at the second, third, and
fourth floors. If it is equally likely that a passenger gets off
at any of the three floors, what is the probability that the
passengers get off at different floors?First we get the numerator of the probability:
There are 3 ways to pick the floor for passenger 1 to get off.
For each of those 3 ways to pick the floor for passenger 1 to get
off, there remain 2 ways to pick a different floor for passenger 2
to get off.
So the numerator of the probability is 3×2 or 6.
Next we get the denominator of the probability:
There are 3 ways to pick the floor for passenger 1 to get off.
For each of those 3 ways to pick the floor for passenger 1 to
get off, there are still 3 ways to pick a floor for passenger
2 to get off.
So the denominator of the probability is 3×3 or 9.
Answer:
Edwin