Question 1107809: Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.)
Find the probability that if Air-USA books 15 persons, not enough seats will be available.
prob =
(round to 4 decimal places)
Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less?
yes, it is low enough not to be a concern
no, it is not low enough to not be a concern
What about defining unusual as 10% or less?
yes, it is low enough not to be a concern
no, it is not low enough to not be a concern
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Air-USA has a policy of booking as many as 15 persons on an airplane that can seat only 14. (Past studies have revealed that only 83% of the booked passengers actually arrive for the flight.)
Find the probability that if Air-USA books 15 persons, not enough seats will be available.
prob = (0.83)^15 = 0.0611
(round to 4 decimal places)
Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less?
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no, it is not low enough to not be a concern
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What about defining unusual as 10% or less?
yes, it is low enough not to be a concern
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Cheers,
Stan H.
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