SOLUTION: Assuming a telemarketer has a 20% chance of selling item A to each caller, a 40 % chance of selling item B to each caller, and the event of selling item A is independent to the eve

Algebra ->  Probability-and-statistics -> SOLUTION: Assuming a telemarketer has a 20% chance of selling item A to each caller, a 40 % chance of selling item B to each caller, and the event of selling item A is independent to the eve      Log On


   



Question 1102448: Assuming a telemarketer has a 20% chance of selling item A to each caller, a 40 % chance of selling item B to each caller, and the event of selling item A is independent to the event of selling item B. Each call in which the telemarketer sells both item A and item B takes 150 seconds, each call that sells only one item (item A or item B but not both) takes 60 seconds and each call that doesn't sell any items takes 30 seconds. If the telemarketer makes 45 calls, what is the average amount of time it takes?
Answer : 2376 Second

Answer by greenestamps(13195) About Me  (Show Source):
You can put this solution on YOUR website!


The probability that item A sells is .2; the probability that it does not sell is 1-.2=.8.
The probability that item B sells is .4; the probability that it does not sell is 1-.4=.6

The probability that both items sell is (.2)(.4)=.08.
The probability that item A sells and item B does not sell is (.2)(.6)=.12.
The probability that item B sells and item A does not sell is (.4)(.8)=.32.
The probability that neither item sells is (.8)(.6)=.48.

The average amount of time in seconds for a call (the expected value) is
.08%28150%29%2B.12%2860%29%2B.32%2860%29%2B.48%2830%29+=+52.8

The expected amount of time for 45 calls is 52.8%2A45=2376