Question 1100140: Could someone please correct my work to see if im doing this right?
A fishing magazine collected data and printed the following results:
If there is rain then the probability of catching a fish at Lake Blue is 80%, but if it doesn't rain then the probability of catching a fish at Lake Blue is 17%. The forecast for today is 68% chance of rain.
A) Draw a tree diagram
(sorry if it looks confusing)
Percent = 100%
80%
R - / 17% R
\ 83 R (not)
/68% R
R (not rain)
20%
\ 32% R(not)
b) What is the probability that it rained today and a fish was caught?
P(RR) = 0.20 x 0.68 = 0.136
c) What is the probability of catching a fish today?
P(R not R|R) = 0.20 x 0.68 = 0.136
d) If a person caught a fish, what is the that there was rain?
I don't get this question*
Thanks
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! Just a guess but "If a person caught a fish, what is the that there was rain?"
might mean "If a person caught a fish, what is the probability that there was rain?"
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