SOLUTION: the mark vi monorail used at disney world has doors with a height of 72 inches. heights of men normally distributed with a mean of 69.4 inches and a standard deviation of 2.2 inche
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Question 1091258: the mark vi monorail used at disney world has doors with a height of 72 inches. heights of men normally distributed with a mean of 69.4 inches and a standard deviation of 2.2 inches
A. what percentage of adult men can fit through the doors without bending?
B. what doorway height would allow 99% of adult men to fit without bending? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! z=(x-mean)/sd
want z for a mean of 69.4
percent of men over 72 inches
z=(72-69.4)/2.2=1.182
z <+1.182 is the probability desired,of 0.8814 or 88.1%
for 99%, need the value of z (0.99), which is +2.328
multiply that by the sd and get 5.1216. That is the difference between the mean and the height of the door.
The door height needs to be 69.4+5.1 or 74.5 inches.
