Question 1090352: A fair die tossed twice. Find probability getting A 4,5 or 6 on the first toss and A 1,2,3 or 4 on second toss ?
Answer by math_helper(2461) (Show Source):
You can put this solution on YOUR website! P(4,5,6) = 3/6
P(1,2,3,4) = 4/6
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The events are independent so we multiply the individual probabilities to get the overall probability:
P(4,5,6) * P(1,2,3,4) = (3/6)*(4/6) = 12/36 =
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