SOLUTION: Let X1,…,X49 be identically distributed independent random variables with Var(Xi)=36 What is the standard deviation of their average X¯=(X1+…+X49)/49?

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Question 1089659: Let X1,…,X49 be identically distributed independent random variables with Var(Xi)=36
What is the standard deviation of their average X¯=(X1+…+X49)/49?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


The standard deviation is the square root of the variance.

John

My calculator said it, I believe it, that settles it