SOLUTION: A poll is conducted to estimate the proportion of students who eat regularly in the cafeteria. A sample of 275 students result in 180 who said they do eat regularly on the cafeteri
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Question 1088232: A poll is conducted to estimate the proportion of students who eat regularly in the cafeteria. A sample of 275 students result in 180 who said they do eat regularly on the cafeteria. Estimate the true proportion of students who eat regularly with 95% certainty. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! We can measure with 95% confidence, not 95% certainty.
the proportion is 180/275=0.655
the interval is +/-1.96*sqrt(0.655*0.345)/275)
the sqrt factor is 0.0287
the interval is that *1.96=0.0562
the CI is (0.598, 0.711)
