SOLUTION: A shipment of 13 televisions contains 5 regular and 8 deluxe models. The manufacturer failed to mark the model designation on the cartons. If 3 cartons are selected at random, what

Algebra ->  Probability-and-statistics -> SOLUTION: A shipment of 13 televisions contains 5 regular and 8 deluxe models. The manufacturer failed to mark the model designation on the cartons. If 3 cartons are selected at random, what      Log On


   

Question 1086165: A shipment of 13 televisions contains 5 regular and 8 deluxe models. The manufacturer failed to mark the model designation on the cartons. If 3 cartons are selected at random, what is the probability that exactly 2 of them are the deluxe model? (Round your answer to three decimal places.)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Without regard for how they are different, how
many 3-carton groups can be picked?
C( 13,3 ) = +13%21+%2F+%28%28+13+-+3+%29%21%2A3%21+%29+
C( 13,3 ) = +13%21+%2F+%28+10%21%2A3%21+%29+
C( 13,3 ) = +%28+11%2A12%2A13+%29+%2F+%28+3%2A2%2A1+%29+
C( 13,3 ) = +286+
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How many different ways can 2 out of the 8
delux models be picked?
C( 8,2 ) = +8%21+%2F+%28%28+8+-+2+%29%2A2%21+%29+
C( 8,2 ) = +8%21+%2F+%28+6%21%2A2%21+%29+
C( 8,2 ) = +%28+7%2A8+%29+%2F+2+
C( 8,2 ) = +28+
Each of these can be matched with 1 of 5 regular models
+28%2A5+=+140+
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The probability is:
+140+%2F+286+=+.4895+
rounded off:
++P+=+.490+
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Definitely get another opinion on this!