SOLUTION: A box of chocolates contains 24 chocolates. Ten of the chocolates have cherry centers. All chocolates appear the same.
Two chocolates are selected. Find the probability of each o
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-> SOLUTION: A box of chocolates contains 24 chocolates. Ten of the chocolates have cherry centers. All chocolates appear the same.
Two chocolates are selected. Find the probability of each o
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Question 1086164: A box of chocolates contains 24 chocolates. Ten of the chocolates have cherry centers. All chocolates appear the same.
Two chocolates are selected. Find the probability of each of the following. (Round your answers to four decimal places.)
(a) both have cherry centers
(b) one has a cherry center and one does not Found 2 solutions by Boreal, ikleyn:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! a)(10/24)(9/23)=90/552=15/92=0.163
b)2*(10/24)(14/23), because two ways to choose it. That is 280/552=0.507
Check with probability both do not, the last choice
(14/24)(13/23)=182/552, and the three add to 552/552.
You can put this solution on YOUR website! .
A box of chocolates contains 24 chocolates. Ten of the chocolates have cherry centers. All chocolates appear the same.
Two chocolates are selected. Find the probability of each of the following. (Round your answers to four decimal places.)
(a) both have cherry centers
(b) one has a cherry center and one does not
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(a) The probability = .
= = 45; = = 276.
Therefore, the probability = = = 0.1630.
The full event space consists of = 276 events.
The "happy" event space consists of = 45 events.
