SOLUTION: A brand name has a 60​% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small sample of 6 randomly selected consumers.
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Question 1086135: A brand name has a 60% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small sample of 6 randomly selected consumers.
What is the probability that exactly 5 of the selected consumers recognize the brand name?
. What is the probability that all of the selected consumers recognize the brand name?
What is the probability that at least 5 of the selected consumers recognize the brand name?
If 66 consumers are randomly selected, is 55 an unusually high number of consumers that recognize the brand name? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Exactly 5 is 6C5 (6 ways to choose them) (.6)^5*.4=6*.0311=0.187
All of them is 0.6^6=0.047
at least 5 is the sum of the first two or 0.234
Can do it with normal approximation or binomial
binomial is 66C55*.6^55*.4^11=0.000028
normal has mean of 66*0.6=39.6
sd is sqrt (66*0.6*0.4)=sqrt(15.84)=3.98
do it greater than 54.5 for continuity correction.
z>=(54.5-39.6)/3.98>=+3.74
This probability is 0.00009.
Yes, it would be an unusually high number of consumers.