Question 1082727: A standard roulette wheel contains the numbers 1-36, and two spaces marked “0” and “00.” Half of the numbers are labeled black, and half of the numbers are labeled red. The numbers “0” and “00” are labeled green. Half of the red and black slots have even numbers, the other half odd numbers. When the wheel is spun, a ball rolls along the outer edge of the wheel until it falls into one of the numbered slots. What is the probability that the ball lands on an even number or a black number?
A) 27/38
B) 1/2
C) 2/18
D) 19/36
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! It is even for half and black for half and double counted for a quarter.
Therefore, it is (18+18-9)/28=27/38. There are 38 possibilities, so the denominator has to be 38 or the fraction 19/38 which can't happen with this question.
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