Question 1071673: I really do not understand what to do in this question and how to solve it.
Nathan tosses 2 coins at the same time. He does this 100 times. Enter the number of times the coins are expected to land as 2 heads.
Found 2 solutions by Edwin McCravy, addingup:
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website!
There are four ways they can land.
1. Head on the first coin, head on the second coin.
2. Head on the first coin, tail on the second coin.
3. Tail on the first coin, head on the second coin.
4. Tail on the first coin, tail on the second coin.
Those four are equally likely, so the probability of
getting two heads is 1 time out of 4, or 1/4, or
25 times out of 100. [Take 1/4 of 100]
Answer; 25.
Edwin
Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! you have 4 possibilities when you toss 2 coins.
HH, TT, TH, HT
So out of 4 possibilities, head:head is 1 or 1/4
Each event is independent, each time you toss the coins is a separate event.
Thus: 1/4*100 = 25 times you can expect to land 2 heads.
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