SOLUTION: a jury consists of five men and seven women. Three are selected at random for an interview. Find the probability that all three are men.
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Question 1062126: a jury consists of five men and seven women. Three are selected at random for an interview. Find the probability that all three are men.
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
There are 5+7 = 12 total people.
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The probability that the first person picked is a man is 5/12.
Pr{2nd is also a man} = 4/11
Pr(3rd is also a man) = 3/10
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Pr{all 3 are men} = (5/12)(4/11)(3/10) = 60/1320 = 1/22 = 0.04545....
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