Question 1056367: In the week before and the week after a holiday, there were 10,000
total deaths, and 4941 of them occurred in the week before the holiday.
a. Construct a 95%
confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday.
b. Based on the result, does there appear to be any indication that people can temporarily postpone their death to survive the holiday?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The CI has a SE of z(0.975,1.96)sqrt{(p)(1-p)/n}
=sqrt {(0.4941)(0.5059)/10000}=0.005
1.96*005=0.0098
The CI is {0.4843,0.5099)
There is no evidence that the deaths differed from 0.5, since the CI includes the parameter.
More importantly, there is no evidence that people can temporarily postpone their death, unless they are suicidal or they live in a state where Death with Dignity is allowed. Because something occurs does not mean that what is postulated as a cause is in fact the cause.
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