Question 1055457: HI TUTORS,
HERE ARE A SET OF DATA FOR THE WOMEN'S I HAVE FOUND THE MEAN, MEDIAN, RANGE AND STANDARD DEVIATION IS MY ANSWERS CORRECT?
49.56
49.75
49.86
49.94
49.99
49.99
50.34
50.47
50.48
50.84
51.02
51.42
51.49
51.54
51.64
51.80
51.94
for the mean I HAVE 50.705882352941 Median: 50.48 Mode: 49.99, 51.42 Standard deviation (σ): 0.77533339184627 Lower quartile: 49.965 Upper quartile: 51.48 for the lowest value: 49.56 highest value: 51.94 Range: 2.38. Sample Standard Deviation, s 0.79919536741282, Variance (Sample Standard), s2 0.63871323529412, sum: 862
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! Recommend using www.numberempire.com/statisticscalculator.php
to check Your answers:
Important to know in finding variance..if using n 0r (n-1) as a divisor is preferred.
Input values
49.56 49.75 49.86 49.94 49.99 49.99 50.34 50.47 50.48 50.84 51.02 51.42 51.49 51.54 51.64 51.8 51.94
Mean
50.71
Variance
0.607294
Corrected variance
0.64525
Standard deviation
0.779291
Corrected standard deviation
0.803275
Median
50.48
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