Question 1054380: An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of 5 emails per hour. Assume the arrival of these emails is approximated by the Poisson distribution.
What is the probability Linda Lahey, company president, received exactly 2 email between 4 P.M. and 5 P.M. yesterday? (Round your answer to 4 decimal places.)
What is the probability she received 4 or more emails during the same period? (Round your answer to 4 decimal places.)
What is the probability she did not receive any emails during the period? (Round your answer to 4 decimal places.)
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! P(x = 2)
The syntax is poissonpdf(mean, x-value).
P(x = 2) = poissonpdf(5, 2) = .0842
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P(x>=4) = 1 - P(x <= 3)
The syntax is poissioncdf(mean, largest x-value).
P(x>=4) = 1 - poissoncdf(5,3) = 1 - .2650 = .7350
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P(x = 0 ) = poissonpdf(5, 0) = .0067
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