SOLUTION: The probability that John will drive to school is 0.37, the probability that he will ride with friends is 0.23, and the probability that his parents will take him is 0.4. He is not
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-> SOLUTION: The probability that John will drive to school is 0.37, the probability that he will ride with friends is 0.23, and the probability that his parents will take him is 0.4. He is not
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Question 1050660: The probability that John will drive to school is 0.37, the probability that he will ride with friends is 0.23, and the probability that his parents will take him is 0.4. He is not allowed to have passengers in the car when he is driving. What is the probability that John will have company on the way to school? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! P(company) = P(ride with friends) + P(with parents) = .23 + .4 = .63 0r 63%
The 3 different case scenarios are independent of one another:.37 + .23 + .4 = 1
P of two of them occurring is found by adding their individual Probabilities
