Question 1048572: A fast-food restaurant chain with 700 outlets in the United States describes the geographic location of its restaurants with the accompanying table of percentages. A restaurant is to be chosen at random from the 700 to test market a new style of chicken. Given that the restaurant is located in the eastern United States, what is the probability it is located in a city with a population of at least 10,000?
Population of City | NE | SE | SW | NW
.............. < 10,000 | 7% | 6% | 3% | 0%
.10,000 to 100,000 | 15%| 3% | 12%| 5%
............. > 100,000 | 20%| 4% | 1% | 24%
a) 0.764
b) 0.5
c) 0.236
d) 0.42
Guessed d) .42 and got it wrong. How do I solve this?
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Population of City | NE | SE | SW | NW
... < 10,000 | 7% | 6% | 3% | 0%
.10,000 to 100,000 | 15%| 3% | 12%| 5%
.... > 100,000 | 20%| 4% | 1% | 24%
total 42% 13%
P(>=10,000 |Eastern) | reads "Given"
P(A|B) = P(A and B)/P(B)
P(>=10,000 |Eastern) = P(>=10000 and Eastern)/P(Eastern) = = 42/55 = .764
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