SOLUTION: the age of a machine X in years is, is related to the probability of breakdown, y by the formula x=3+Ln(y/1-y) Determine the probability of a breakdown for 1 3 and 10 years. x

Algebra ->  Probability-and-statistics -> SOLUTION: the age of a machine X in years is, is related to the probability of breakdown, y by the formula x=3+Ln(y/1-y) Determine the probability of a breakdown for 1 3 and 10 years. x       Log On


   



Question 1030969: the age of a machine X in years is, is related to the probability of breakdown, y by the formula x=3+Ln(y/1-y)
Determine the probability of a breakdown for 1 3 and 10 years.
x = 3 + l n ( y 1 − y )
x=3+ln(y1−y)
3 + l n ( y 1 − y )
= 1 3+ln(y1−y)
=1 3 + l n ( y 1 − y )
= 3 3+ln(y1−y)=3
3 + l n ( y 1 − y ) = 10
I'm lost, lost lost!

Answer by Alan3354(69443) About Me  (Show Source):
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the age of a machine X in years is, is related to the probability of breakdown, y by the formula x=3+Ln(y/1-y)
Determine the probability of a breakdown for 1 3 and 10 years.
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Solve for y:
x = 3 + ln(y/1-y)
x - 3 = ln(y/1-y)
y/(1-y) = e^(x-3)
y/(y-1) = -e^(x-3)
y = -e^(x-3)(y-1) = -e^(x-3)*y + e^(x-3)
y + e^(x-3)*y = e^(x-3)
y*(e^(x-3) + 1) = e^(x-3)
y+=+e%5E%28x-3%29%2F%28e%5E%28x-3%29+%2B+1%29
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x = 1 year
y = e^(-2)/(e^(-2)+1)
y =~ 0.1192
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x = 3 years
y = e^0/(e^0 + 1)
y = 0.5
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x = 10 years
y = e^(7)/(e^(7)+1)
y =~ 0.9991