Question 1029248: The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is normally distributed. If a sample of 10 dinners is selected, find the probability that the mean of the sample will be larger than 670 mg.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The average number of milligrams (mg) of sodium in a certain brand of low-salt microwave frozen dinners is 660 mg, and the standard deviation is 35 mg. Assume the variable is normally distributed. If a sample of 10 dinners is selected, find the probability that the mean of the sample will be larger than 670 mg.
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t(670) = (670-660)/[35/sqrt(10)] = 0.9035
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P(x-bar > 670) = P(t > 0.9035 when df = 9) = tcdf(0.9035,100,9) = 0.1949
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Cheers,
Stan H.
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