SOLUTION: Suppose GRE Verbal scores are normally distributed with a mean of 459 and a standard deviation of 120. A university plans to offer tutoring jobs to students whose scores are in th

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Question 1026629: Suppose GRE Verbal scores are normally distributed with a mean of 459 and a standard deviation of 120. A university plans to offer tutoring jobs to students whose scores are in the top 14%. What is the minimum score required for the job offer?
Found 2 solutions by stanbon, mathmate:
Answer by stanbon(75887) About Me  (Show Source):
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Suppose GRE Verbal scores are normally distributed with a mean of 459 and a standard deviation of 120. A university plans to offer tutoring jobs to students whose scores are in the top 14%. What is the minimum score required for the job offer?
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Find the z-score with a left tail of 0.86
invNorm(0.86) = 1.0803
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Solve for "x" using x = z*s + u
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x = 1.0803*120 + 459 = 588.64
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Cheers,
Stan H.
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Answer by mathmate(429) About Me  (Show Source):
You can put this solution on YOUR website!

Question:
Suppose GRE Verbal scores are normally distributed with a mean of 459 and a standard deviation of 120. A university plans to offer tutoring jobs to students whose scores are in the top 14%. What is the minimum score required for the job offer?

Solution:
Top 14% means that 86% of the students are below.
The corresponding Z-score can be read from the Normal Distribution table as:
P(Z≤1.0803)=86% (left-tail only).
So convert to number of students,
Z=(X-μ)/σ
means that
X=Z*σ+&mu=1.0803*120+459=588.6
So minimum score is 588.6 to be in the top 14%.