SOLUTION: a bag contains 15 identical discs.there are 8 red,4 blue and 3 white discs.A disc is picked out at random and not replaced.A second disc is then picked out at random and not replac

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Question 1025309: a bag contains 15 identical discs.there are 8 red,4 blue and 3 white discs.A disc is picked out at random and not replaced.A second disc is then picked out at random and not replaced.A third disc is now picked out at random.Calculate the probability that none of the three discs is white.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Look at the possible outcomes.
RRR
RRW
RRB
.
.
.
BBR
BBW
BBB
Out of the possible 27 outcomes, 9 start with a white chip.
Of the remaining 18 outcomes, 6 have a middle white chip.
Of the remaining 12 outcomes, 4 have a last white chip.
That leaves 8 outcomes that don't have a white chip.
RRR
RRB
RBR
RBB
BRR
BRB
BBR
BBB
Look at the occurences of R in the outcomes,
3 R=1
2 R=3
1 R=3
0 R=1
P%283R%29=+%288%2F15%29%287%2F14%29%286%2F13%29+=336%2F2730+
P%282R%29=+%288%2F15%29%287%2F14%29%284%2F13%29+=224%2F2730+
P%281R%29=+%288%2F15%29%284%2F14%29%283%2F13%29+=96%2F2730+
P%280R%29=+%284%2F15%29%283%2F14%29%282%2F13%29+=24%2F2730+
So then,
P=+%28336%2B3%28224%29%2B3%2896%29%2B24%29%2F2730+
P=44%2F91