SOLUTION: Find the mean and standard deviation of x for binomial probabltiy distribution with n=100 and p=0.3?

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Question 1023359: Find the mean and standard deviation of x for binomial probabltiy distribution with n=100 and p=0.3?
Found 2 solutions by Tatiana_Stebko, mathmate:
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
The mean of x is m=np=100%2A0.3=30
The standard deviation of x is s=sqrt%28np%281-p%29%29=sqrt%28100%2A0.3%2A%281-0.3%29%29=sqrt%2821%29=4.5826

Answer by mathmate(429) About Me  (Show Source):
You can put this solution on YOUR website!

Question:
Find the mean and standard deviation of x for binomial probability distribution with n=100 and p=0.3?

Solution:
The mean (μ) and standard deviation (σ) of the given distribution can be found according to standard formulae:
Mean (μ) = np
Standard Deviation (σ) = √(npq)
where n=number of Bernoulli steps in the experiment,
p=probability of success
q=(1-p)=probability of failure.

For the given problem,
n=100
p=0.3
q=(1-0.3)=0.7
therefore
mean=np=100*0.3=70
standard deviation=√(npq)
=√(100*0.3*0.7)
=√(21)
=4.583 (approximately)