SOLUTION: A fair coin is tossed. If a head turns up, a fair die is tossed ; if a tail turns up, 2 fair dice are tossed. What is the probability that the face (or sum of the faces) o

Algebra ->  Probability-and-statistics -> SOLUTION: A fair coin is tossed. If a head turns up, a fair die is tossed ; if a tail turns up, 2 fair dice are tossed. What is the probability that the face (or sum of the faces) o      Log On


   

Question 1016318: A fair coin is tossed. If a head turns up, a fair die is
tossed ; if a tail turns up, 2 fair dice are tossed. What
is the probability that the face (or sum of the faces)
or the die (or dice) is equal to 6?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
P(T&6 or H&1&5 or H&2&4 or H&3&3 or H&4&2 or H&5&1) =

P(T&6) + P(H&1&5) + P(H&2&4) + P(H&3&3) + P(H&4&2) + P(H&5&1)

P(T&6) = (1/2)(1/6) = 1/12 =  6/72
P(H&1&5) = (1/2)(1/6)(1/6) =  1/72
P(H&2&4) = (1/2)(1/6)(1/6) =  1/72
P(H&3&3) = (1/2)(1/6)(1/6) =  1/72
P(H&4&2) = (1/2)(1/6)(1/6) =  1/72
P(H&5&1) = (1/2)(1/6)(1/6) =  1/72 
----------------------------------
                     Total = 11/72 

Edwin